(27^x+3)/(81^x-1)=9

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Solution for (27^x+3)/(81^x-1)=9 equation: 



(27^x+3)/(81^x-1)=9

We move all terms to the left:

(27^x+3)/(81^x-1)-(9)=0



Domain of the equation: (81^x-1)!=0

We move all terms containing x to the left, all other terms to the right

81^x!=1

x!=1/1

x!=1

x∈R



We multiply all the terms by the denominator


(27^x+3)-9*(81^x-1)=0

We multiply parentheses

(27^x+3)-729x+9=0

We get rid of parentheses

27^x-729x+3+9=0

We add all the numbers together, and all the variables

-729x+27^x+12=0

We move all terms containing x to the left, all other terms to the right

-729x+27^x=-12

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